15-0.06x^2=0

Solution for 15-0.06x^2=0 equation:

15-0.06x^2=0

a = -0.06; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-0.06)·15
Δ = 3.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.6}}{2*-0.06}=\frac{0-\sqrt{3.6}}{-0.12}
=-\frac{\sqrt{}}{-0.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.6}}{2*-0.06}=\frac{0+\sqrt{3.6}}{-0.12}
=\frac{\sqrt{}}{-0.12}
$